20q^2+q-1=

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Solution for 20q^2+q-1= equation:


Simplifying
20q2 + q + -1 = 0

Reorder the terms:
-1 + q + 20q2 = 0

Solving
-1 + q + 20q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(-1 + -4q)(1 + -5q) = 0

Subproblem 1

Set the factor '(-1 + -4q)' equal to zero and attempt to solve: Simplifying -1 + -4q = 0 Solving -1 + -4q = 0 Move all terms containing q to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -4q = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -4q = 0 + 1 -4q = 0 + 1 Combine like terms: 0 + 1 = 1 -4q = 1 Divide each side by '-4'. q = -0.25 Simplifying q = -0.25

Subproblem 2

Set the factor '(1 + -5q)' equal to zero and attempt to solve: Simplifying 1 + -5q = 0 Solving 1 + -5q = 0 Move all terms containing q to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -5q = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -5q = 0 + -1 -5q = 0 + -1 Combine like terms: 0 + -1 = -1 -5q = -1 Divide each side by '-5'. q = 0.2 Simplifying q = 0.2

Solution

q = {-0.25, 0.2}

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